Proof of Put-Call Parity with/without dividend

(Reference)

1. Without Dividend

(Before we begin...) What is Put-Call Parity?

 \displaystyle C-P=S-d \cdot K

Put-Call Parity is a relation between put price and call price shown above.

The meaning of alphabets are:

  • C : Call option's price (now)
  • P : Put option's price (now)
  • S : Stock price (now)
  • d : Discount factor. It takes value between 0~1, exclusive.
  • K : Strike price of call and put option (we assume that call option and put option have the same strike price)

Proof

Assume  S_{T} is a stock price at the end

  • Cost of buying one unit of stock =  S
  • Payoff buying one unit of stock = S_{T}

Then create a portfolio which includes:

  1. Buy one call
  2. Short sell one put
  3. Lend  d \cdot K to a bank

Then,

  • The cost of creating the portfolio =  C - P + d \cdot K
  • Payoff of the portfolio =

 \displaystyle  \max (0, S_{T} - K)

 \displaystyle - \max (0, K - S_{T}) + K

 \displaystyle = S_{T}

Here, the stock and the portfolio has the same payoff at the end.

Therefore, based on the no-arbitrage assumption, they should have the same cost.

Hence,  S = C - P + d \cdot K


2. With Dividend

The equation we want to prove is:

 \displaystyle C-P+D =S - d \cdot K

Where D is the dividend's present value.

Proof

Assume  S_{T} is a stock price at the end

  • Cost of buying one unit of stock =  S
  • Payoff buying one unit of stock = S_{T} + \frac{D}{d}

Then create a portfolio which includes:

  1. Buy one call
  2. Short sell one put
  3. Lend  D + d \cdot K to a bank

Then,

  • The cost of creating the portfolio =  C - P + D + d \cdot K
  • Payoff of the portfolio =

 \displaystyle \max (0, S_{T} - K)

 \displaystyle - \max (0, K - S_{T}) + K

 \displaystyle  + \frac{D}{d}

 \displaystyle = S_{T} + \frac{D}{d}

Here, the stock and the portfolio has the same payoff at the end.

Therefore, based on the no-arbitrage assumption, they should have the same cost.

Hence,  \displaystyle  S = C - P + D + d \cdot K

 \displaystyle  \iff C-P+D =S - d \cdot K